16x^2+12x=27

Solution for 16x^2+12x=27 equation:

16x^2+12x=27

We move all terms to the left:

16x^2+12x-(27)=0

a = 16; b = 12; c = -27;
Δ = b2-4ac
Δ = 122-4·16·(-27)
Δ = 1872
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1872}=\sqrt{144*13}=\sqrt{144}*\sqrt{13}=12\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{13}}{2*16}=\frac{-12-12\sqrt{13}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{13}}{2*16}=\frac{-12+12\sqrt{13}}{32}
$